參數(shù)資料
型號: M80C186EB-13
廠商: Intel Corp.
英文描述: 16-Bit High-Integration Embedded Processor(16位高集成嵌入式處理器)
中文描述: 16位高性能嵌入式處理器集成(16位高集成嵌入式處理器)
文件頁數(shù): 18/56頁
文件大小: 855K
代理商: M80C186EB-13
M80C186EB
Table 4. M80C186EB Pin Descriptions
(Continued)
Name
Type
Description
INT0
INT1
INT4
I
Maskable
INTerrupt
input will cause a vector to a specific Type interrupt
routine. To allow interrupt expansion, INT0 and/or INT1 can be used with
INTA0 and INTA1 to interface with an external slave controller.
A(E,L)
INT2/INTA0
INT3/INTA1
I/O
A(E,L)
/H(1)
R(Z)
/P(1)
These pins provide a multiplexed function. As inputs, they provide a
maskable
INTerrupt
that will cause the CPU to vector to a specific Type
interrupt routine. As outputs, each is programmatically controlled to provide
an INTERRUPT ACKNOWLEDGE handshake signal to allow interrupt
expansion.
P2.7
P2.6
I/O
A(L)
H(X)
R(Z)
P(X)
Bidirectional, open-drain
Port
pins.
CTSO
P2.4/CTS1
I
Clear-To-Send
input is used to prevent the transmission of serial data on
their respective TXD signal pin. CTS1 is multiplexed with an input only port
function.
A(L)
TXD0
P2.1/TXD1
O
Transmit Data
output provides serial data information. TXD1 is multiplexed
with an output only
Port
function. During synchronous serial
communications, TXD will function as a clock output.
H(X)/H(Q)
R(1)
P(X)/P(Q)
RXD0
P2.0/RXD1
I/O
A(L)
R(Z)
H(Q)
P(X)
Receive Data
input accepts serial data information. RXD1 is multiplexed
with an input only
Port
function. During synchronous serial communications,
RXD is bi-directional and will become an output for transmission or data
(TXD becomes the clock).
P2.5/BCLK0
P2.2/BCLK1
I
Baud CLocK
input can be used as an alternate clock source for each of the
integrated serial channels. BCLKx is multiplexed with an input only
Port
function, and cannot exceed a clock rate greater than one-half the
operating frequency of the M80C186EB.
A(L)/A(E)
P2.3/SINT1
O
Serial INTerrupt
output will go active to indicate serial channel 1 requires
service. SINT1 is multiplexed with an output only
Port
function.
H(X)/H(Q)
R(0)
P(X)/P(Q)
18
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