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參數(shù)資料
| 型號： | CX74038-12 |
| 廠商： | SKYWORKS SOLUTIONS INC |
| 元件分類： | XO, clock |
| 英文描述： | 2.6 GHz/800 MHz Dual Fractional-N/lnteger-N Frequency Synthesizer |
| 中文描述： | PLL FREQUENCY SYNTHESIZER, 2600 MHz, PDSO20 |
| 封裝： | 6.5 X 4.4 MM, 1 MM HEIGHT, TSSOP-20 |
| 文件頁數(shù)： | 8/12頁 |
| 文件大?。?/td> | 114K |
| 代理商： | CX74038-12 |
DATA SHEET CX74038
Skyworks Solutions, Inc. Phone [781] 376-3000 Fax [781] 376-3100 sales@skyworksinc.com www.skyworksinc.com
101075I Skyworks Proprietary and Confidential information Products and product information are subject to change without notice January 31, 2005
5
Case 1: To achieve a desired FVCO_RF frequency of 2440.2 MHz using a crystal frequency of 24 MHz with operation
of the synthesizer in RF mode using the 16/17 prescaler (PS = 1). R1 is set to divide by 3 to achieve a
comparison frequency of 8 MHz, since the maximum internal reference frequency is 9 MHz. Divide the operating
frequency by the internal reference frequency to determine the value of NTotal:
NTotal
= 2440.2 MHz
8 MHz
=
305.025
Subtract 3.5 from NTotal and remove the fractional portion of the result to determine N1:
305.025 – 3.5 = 301.525
N1 = 301 (decimal)
Fractional portion = 0.525 (decimal)
N1 = 000100101101 (binary)
D21 -----------D10 Register Address 112
Multiply the fractional portion of N1 by 256 and remove the fractional portion of the result to determine FN:
0.525 × 256 = 134.4
FN = 134 (decimal)
FN = 10000110 (binary)
D9 -------D2 Register Address 112
Divide FN by 256 to determine the actual fractional portion:
134 = 0.5234375
256
Subtract this result from the fractional portion of N1:
0.525 – 0.5234375 = 0.0015625
Multiply this result by 2097152 (the 21-bit
Σ modulator value 221) and remove the fractional portion to determine
the ME:
0.0015625 × 2097152 = 3276.8
ME = 3276 (decimal)
ME = 0110011001100 (binary)
D21 --------------D9 Register Address 012
In this example, N1 is greater than 256, the minimum divide ratio for the 16/17 prescaler.
C1454
Figure 5. Fractional-N Applications: Sample Calculation (1 of 2)
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