參數(shù)資料
型號(hào): TPA0232PWPRG4
廠商: TEXAS INSTRUMENTS INC
元件分類: 音頻控制
英文描述: 2 CHANNEL(S), VOLUME CONTROL CIRCUIT, PDSO24
封裝: GREEN, PLASTIC, TSSOP-24
文件頁(yè)數(shù): 16/36頁(yè)
文件大?。?/td> 805K
代理商: TPA0232PWPRG4
www.ti.com
BTL AMPLIFIER EFFICIENCY
V(LRMS)
VO
IDD
IDD(avg)
TPA0232
SLOS286D – NOVEMBER 1999 – REVISED SEPTEMBER 2004
Class-AB amplifiers are inefficient, primarily because of voltage drop across the output-stage transistors. The two
components of the internal voltage drop are the headroom or dc voltage drop that varies inversely to output
power, and the sine wave nature of the output. The total voltage drop can be calculated by subtracting the RMS
value of the output voltage from VDD. The internal voltage drop multiplied by the RMS value of the supply current
(IDDrms) determines the internal power dissipation of the amplifier.
An easy-to-use equation to calculate efficiency begins as the ratio of power from the power supply to the power
delivered to the load. To accurately calculate the RMS and average values of power in the load and in the
amplifier, the current and voltage waveforms must be understood (see Figure 38).
Figure 38. Voltage and Current Waveforms for BTL Amplifiers
Although the voltages and currents for SE and BTL are sinusoidal in the load, currents from the supply are very
different between SE and BTL configurations. In an SE application, the current waveform is a half-wave rectified
shape, whereas in BTL it is a full-wave rectified waveform. Therefore, RMS conversion factors are different. Keep
in mind that for most of the waveform both the push and pull transistors are not on at the same time, which
supports the fact that each amplifier in the BTL device only draws current from the supply for half the waveform.
Equation 7 and Equation 8 are the basis for calculating amplifier efficiency.
23
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