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參數(shù)資料
| 型號： | SP8861NAHP |
| 廠商： | Mitel Networks Corporation |
| 英文描述： | 1·3GHz Low Power Single-Chip Frequency Synthesiser |
| 中文描述： | 1.3 GHz的低功耗單芯片頻率合成器 |
| 文件頁數(shù)： | 11/13頁 |
| 文件大?。?/td> | 200K |
| 代理商： | SP8861NAHP |
11
SP8861
Fig. 11 Standard form of third order loop filter
Fig. 12 Modified form of third order loop filter
+
R1
C1
R2
C2
FROM
CHARGE
PUMP
TO VCO
+
R1
C1
R2
Cx
FROM
CHARGE
PUMP
TO VCO
R3
C3
where K
u
,
K
,
N and
v
are as defined for the second order
loop and
F
is the phase margin, normally set to 45
. These
values can now be substituted in equation (3) to obtain a value
for C
and in equations (4) and (5) to determine values for C
2
and R
2
.
Example
Calculate values for a third order loop with parameters as
for the second order loop and
F
0
= 45
°
.
From equation (5):
2
tan
45
°
1
t
3
=
500Hz
3
2
p
0·4142
1
cos 45
°
∴
t
3
=
131·8
μ
s
=
3161·6
From equation (4):
t
2
=
(500
3
2
3p
)
2
3
1·318
3
10
2
4
∴
t
2
=
768·7
μ
s
1
Using these values in equation (3):
t
1
=
8000
3
(500
3
2
p
)
2
7·96
3
10
2
3
3
2
p3
10MHz/V
3
[A]
1
1
v
n
1
1
v
n
1
1
(500
3
2
p
)
2
3
(7·687
3
10
2
4
)
2
1
1
(500
3
2
p
)
2
3
(1·318
3
10
2
4
)
2
2
t
2
2
t
3
2
2
where A =
=
1
2
t
1
=
7·896
1
10
10
500141·6
6·832
1·1714
1
2
= 6·334
3
10
2
6
3
2·415
∴
t
1
=
15·3
μ
s
Now, since
t
1
=
C
1
R
1
and R
1
=1k
, C
1
=
∴
C
1
=
0·0153
μ
F
3
10
2
5
10
3
For Fig. 11,
t
2
=
R
2
(C
1
1
C
2
)
For Fig. 12,
t
3
=
C
2
R
2
Substituting for C
2
:
t
3
=
C
2
R
2
=
t
2
= R
2
C
1
1
t
3
R
2
= R
2
C
1
1
t
3
t
2
2
t
3
C
1
or,
R
2
=
=7·687
3
10
2
4
2
1·318
3
10
2
4
0·0153
3
10
2
6
∴
R
2
=
41·627k
t
3
R
2
=1·318
3
10
2
4
41627
∴
C
2
=
3·17nF
For Fig. 12,
t
1
=
C
1
R
1
1·53
3
10
2
5
10
3
∴
C
1
=
0·0153nF
or,
C
1
=
∴
R
2
=
50·242k
or,
R
2
=
t
2
=
C
1
R
2
7·687
3
10
2
4
1·53
3
10
2
8
t
3
=
C
2
R
3
Since the values of C
2
and R
3
are independent of the other
components, either can be chosen and the other determined.
Assuming that R
3
= 1k
, then
1·318
3
10
2
4
10
3
∴
C
2
=
0·01318
μ
F
C
2
=
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