參數(shù)資料
型號(hào)： PM6680TR
廠商： STMICROELECTRONICS
元件分類： 穩(wěn)壓器
英文描述： 0.4 A DUAL SWITCHING CONTROLLER, 500 kHz SWITCHING FREQ-MAX, QCC32
封裝： 5 X 5 MM, 1 MM HEIGHT, 0.50 MM PITCH, LEAD FREE, VFQFPN-32
文件頁(yè)數(shù)： 17/49頁(yè)
文件大?。?/td> 2931K
代理商： PM6680TR
Device description
PM6680
24/49
7.3
Output ripple compensation and loop stability
In a classic Constant On Time control, the system regulates the valley value of the output
voltage and not the average value, as shown in Figure 28 In this condition, the output
voltage ripple is source of a DC static error.
To compensate this error, an integrator network can be introduced in the control loop, by
connecting the output voltage to the COMP1/COMP2 (for the OUT1 and OUT2 sections
respectively) pin through a capacitor CINT as in Figure 30
Figure 30.
Circuitry for output ripple compensation
The integrator amplifier generates a current, proportional to the DC errors between the FB
voltage and Vr, which decreases the output voltage in order to compensate the total static
error, including the voltage drop on PCB traces. In addition, CINT provides an AC path for the
output ripple. In steady state, the voltage on COMP1/COMP2 pin is the sum of the reference
voltage Vr and the output ripple (see Figure 30). In fact when the voltage on the COMP pin
reaches Vr, a fixed Ton begins and the output increases.
For example, we consider Vout = 5 V with an output ripple of
V = 50 mV. Considering
CINT >> CFILT, the CINT DC voltage drop VCINT is about 5 V-Vr+25 mV = 4.125 V. CINT
assures an AC path for the output voltage ripple. Then the COMP pin ripple is a replica of
the output ripple, with a DC value of Vr + 25 mV = 925 mV.
For more details about the output ripple compensation network, see the Section 7.13.6:
In steady state the FB pin voltage is about Vr and the regulated output voltage depends on
the external divider:
Equation 4
+
-
V
Vrr
C
CO
OM
MP
P
g
gm
m
O
OU
UT
T
V
Vrr
+
P
PW
WM
M
C
Co
om
mp
pa
arra
atto
orr
C
CIINNTT
R
RIINNTT
C
CFFIILLTT
t
Vr
C
COOUUTT
COMP PIN
VOLTAGE
L
D
OUTPUT
VOLTAGE
I=gm(V1-Vr)
V
V1
1
t
V
VCCIINNTT
R
ROOUUTT
F
FB
B
R
R11
R
R22
OUT
Vr
1
R
2
R
1
-------
+
×
=
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