參數(shù)資料
型號(hào): LT1397
廠商: Linear Technology Corporation
英文描述: Quad 400MHz Current Feedback Amplifier(四路400MHz電流反饋放大器)
中文描述: 四400MHz的電流反饋放大器(四路400MHz的電流反饋放大器)
文件頁(yè)數(shù): 11/16頁(yè)
文件大小: 258K
代理商: LT1397
11
LT1395/LT1396/LT1397
U
S
A
Buffered Color-Difference to RGB Matrix
An LT1395 combined with an LT1396 can be used to
create buffered RGB outputs from color-difference sig-
nals (Figure 5). The R output is a back-terminated 75
signal created using resistor R5 and amplifier A1 config-
ured for a gain of +2 via 255
resistors R3 and R4. The
noninverting input of amplifier A1 is connected via 1k
resistors R1 and R2 to the Y and R-Y inputs respectively,
resulting in cancellation of the Y signal at the amplifier
input. The remaining R signal is then amplified by A1.
The B output is also a back-terminated 75
signal
created using resistor R16 and amplifier A3 configured
for a gain of +2 via 255
resistors R14 and R15. The
noninverting input of amplifier A3 is connected via 1k
resistors R12 and R13 to the Y and B-Y inputs respec-
tively, resulting in cancellation of the Y signal at the
amplifier input. The remaining B signal is then amplified
by A3.
The G output is the most complicated of the three. It is a
weighted sum of the Y, R-Y and B-Y inputs. The Y input
is attenuated via resistors R6 and R7 such that amplifier
A2’s noninverting input sees 0.83Y. Using superposition,
we can calculate the positive gain of A2 by assuming that
R8 and R9 are grounded. This results in a gain of 2.41 and
a contribution at the output of A2 of 2Y. The R-Y input is
amplified by A2 with the gain set by resistors R8 and R10,
giving an amplification of –1.02. This results in a contri-
bution at the output of A2 of 1.02Y – 1.02R. The B-Y input
is amplified by A2 with the gain set by resistors R9 and
R10, giving an amplification of –0.37. This results in a
contribution at the output of A2 of 0.37Y – 0.37B.
O
PPLICATI
U
U
If we now sum the three contributions at the output of A2,
we get:
A2
OUT
= 3.40Y – 1.02R – 0.37B
It is important to remember though that Y is a weighted
sum of R, G and B such that:
Y = 0.3R + 0.59G + 0.11B
If we substitute for Y at the output of A2 we then get:
A2
OUT
= (1.02R – 1.02R) + 2G + (0.37B – 0.37B)
= 2G
The back-termination resistor R11 then halves the output
of A2 resulting in the G output.
Figure 5. Buffered Color-Difference to RGB Matrix
+
A2
LT1395
R7
1k
B-Y
R-Y
Y
R10
267
R11
75
R6
205
R2
1k
R1
1k
R8
261
R9
698
+
1/2 A3
R14
267
B
G
R16
75
R12
1k
R13
1k
R15
267
ALL RESISTORS 1%
V
S
=
±
5V
+
1/2 A1
R3
267
R
R5
75
R4
267
1395/6/7 F05
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