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| 型號(hào)： | ECL |
| 英文描述： | ECL Output Termination Techniques (91k) |
| 中文描述： | ECL輸出終端技術(shù)（91k） |
| 文件頁數(shù)： | 2/6頁 |
| 文件大?。?/td> | 91K |
| 代理商： | ECL |
2
www.semtech.com
HIGH-PER.ORMANCE PRODUCTS
Revision 1/January 9, 2002
AN1003
This method does not require an additional power sup-
ply. Basically it requires one pull-up resistor between
the output and VCC and a pull-down resistor between
the output and Vee. The values of these two resistors,
R
P1
& R
P2
, will change depending on the supply voltage
range of the device. The scheme is very easy to imple-
ment and it is cost effective compared to parallel ter-
mination scheme; however, the power consumption on
the external resistors are a little higher. The placement
of these termination resistors must be very close to
its destination for optimum performance. Equations 1
and 2, will allow us to calculate the values of these
termination resistors based on the value of transmis-
sion line impedance. Refer to figure 2 for the sche-
matic and table 3 for R
P1
& R
P2
values for different sup-
ply voltage range and transmission line impedance.
Table 2 depicts average current consumption and power
dissipation for different transmission line impedance
values using Thevenin equivalent parallel termination
scheme.
(
o
Z
)
R 1
P
=
(
o
Z
*
8
.
1
)
R 2
P
=
(
o
Z
*
5
2
.
2
))
A
m
(
g
v
a
I
R
n
o
D
P
1
P
d
n
a
R 2
P
)
W
m
(
0
50
93
1
12
.
8
29
0
1
5
75
3
19
6
18
.
8
17
.
2
7
0
10
8
15
2
21
.
4
15
.
4
5
0
5
10
7
28
3
34
.
93
.
6
3
Table 2
RP1
VEE * RT
VEE - VTT
RP2
VEE * RT
VTT
(1)
(2)
=
o
Z (
)
e
g
a
t
l
o
V
y
l
p
u
S
V
3
.
3
-
r
o
V
3
.
3
+
e
g
a
t
l
o
V
y
l
p
u
S
V
0
.
5
-
r
o
V
0
.
5
+
R 1
P
R 2
P
R 1
P
R 2
P
0
57
2
13
83
85
2
1
5
70
9
14
2
15
2
18
8
1
0
14
5
25
6
17
6
10
5
2
0
5
10
8
38
4
20
5
25
7
3
Table 3
Thevenin Equivalent Parallel Termination
Note:
Numbers in Table 2 assumes VCC = 4.5V.
Thevenin Equivalent Termination Scheme
Typical ECL/PECL Device
VCC
VEE
RP1
Typical ECL/PECL Device
Transmission Line
Zo
Figure 2
RP2
RP1
RP2
Conditions:
RT = Zo, impedance of the transmision line
VTT = VCC - 2.0V
VEE = - 3.0V to - 5.5V, VCC = 0V or
VCC = +3.0V to + 5.5V, VEE = 0V
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