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參數(shù)資料
| 型號： | AD534JH |
| 廠商： | ANALOG DEVICES INC |
| 元件分類： | 運動控制電子 |
| 英文描述： | Dual 14-bit 105MSPS ADC with serialized LVDS output 48-VQFN -40 to 85 |
| 中文描述： | ANALOG MULTIPLIER OR DIVIDER, 1 MHz BAND WIDTH, MBCY10 |
| 封裝： | HERMETIC SEALED, METAL CAN, TO-100, 10 PIN |
| 文件頁數(shù)： | 8/12頁 |
| 文件大?。?/td> | 159K |
| 代理商： | AD534JH |
AD534–Applications Section
–8–
The versatility of the AD534 allows the creative designer to
implement a variety of circuits such as wattmeters, frequency
doublers and automatic gain controls to name but a few.
X
1
X
2
Y
1
Y
2
Z
1
Z
2
AD534
OUTPUT =A
2
– B
2
10V
OUT
–V
S
+V
S
SF
+15V
–15V
A – B
2
A
B
A + B
2
30k
V
10k
V
Figure 8. Difference-of-Squares
X
1
X
2
Y
1
Y
2
Z
1
Z
2
AD534
OUTPUT,
6
12V PK
=E
E
S
0.1V
OUT
–V
S
+V
S
SF
+15V
–15V
SIGNAL INPUT,
E
S
,
6
5V PK
39k
V
1k
V
0.005
m
F
–V
S
CONTROL INPUT,
E
C
, ZERO TO
6
5V
SET
GAIN
1k
V
2k
V
NOTES:
1) GAIN IS X 10 PER-VOLT OF E
, ZERO TO X 50
2) WIDEBAND (10Hz – 30kHz) OUTPUT NOISE IS 3mV RMS, TYP
CORRESPONDING TO A.F.S. S/N RATIO OF 70dB
3) NOISE REFERRED TO SIGNAL INPUT, WITH E
=
6
5V, IS 60
m
V RMS, TYP
4) BANDWITH IS DC TO 20kHz, –3dB, INDEPENDENT OF GAIN
Figure 9. Voltage-Controlled Amplifier
X
1
X
2
Y
1
Y
2
Z
1
Z
2
AD534
OUTPUT = (10V) sin
u
OUT
–V
S
+V
S
SF
+15V
–15V
4.7k
V
4.3k
V
18k
V
10k
V
USING CLOSE TOLERANCE RESISTORS AND AD534L, ACCURACY
OF FIT IS WITHIN
6
0.5% AT ALL POINTS.
u
IS IN RADIANS.
INPUT, E
u
0 TO +10V
WHERE
u
=
p
E
u
2 10V
3k
V
Figure 10. Sine-Function Generator
X
1
X
2
Y
1
Y
2
Z
1
Z
2
OUTPUT = 1
6
E
C
sin
v
t
M
OUT
–V
S
+V
S
SF
+15V
–15V
THE SF PIN OR A Z-ATTENUATOR CAN BE USED TO PROVIDE OVERALL
SIGNAL AMPLIFICATION, OPERATION FROM A SINGLE SUPPLY POSSIBLE;
BIAS Y
2
TO V
S
/2.
CARRIER
INPUT
E
C
sin
v
t
MODULATION
INPUT,
6
E
M
AD534
Figure 11. Linear AM Modulator
9k
V
1k
V
X
1
X
2
Y
1
Y
2
Z
2
Z
1
AD534
OUTPUT = (100V)
(1% PER VOLT)
B
A – B
OUT
–V
S
+V
S
SF
+15V
–15V
OTHER SCALES, FROM 10% PER VOLT TO 0.1% PER VOLT
CAN BE OBTAINED BY ALTERING THE FEEDBACK RATIO.
B INPUT
(+V
E
ONLY)
A INPUT
(
6
)
Figure 12. Percentage Computer
X
1
X
2
Y
1
Y
2
Z
1
Z
2
OUTPUT,
6
5V/PK
= (10V)1 y
(10V)
Y
WHERE y =
OUT
–V
S
+V
S
SF
+15V
–15V
INPUT, Y
6
10V FS
AD534
Figure 13. Bridge-Linearization Function
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