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參數(shù)資料
| 型號(hào)： | TPS61087DSCR |
| 廠商： | TEXAS INSTRUMENTS INC |
| 元件分類： | 穩(wěn)壓器 |
| 英文描述： | 4.8 A SWITCHING REGULATOR, 1500 kHz SWITCHING FREQ-MAX, PDSO10 |
| 封裝： | GREEN, PLASTIC, SON-10 |
| 文件頁數(shù)： | 3/30頁 |
| 文件大小： | 964K |
| 代理商： | TPS61087DSCR |
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avg
out
I
=
D
avg
forward
P
I
V
=
×
2
18
70
1.238
m
=
W
=
FB
V
R
k
A
V
1
2
1
S
FB
V
R
V
=
×
-
÷
è
V
FB
R1
R2
V
S
110
IN
S
out
COMP
out
V
C
R
L I
×
=
×
7.5
s
out
COMP
out
COMP
V
C
I
R
×
=
×
www.ti.com
SLVS821B – MAY 2008 – REVISED MARCH 2010
Rectifier Diode Selection
To achieve high efficiency a Schottky type should be used for the rectifier diode. The reverse voltage rating
should be higher than the maximum output voltage of the converter. The averaged rectified forward current Iavg ,
the Schottky diode needs to be rated for, is equal to the output current Iout :
(6)
Usually a Schottky diode with 2 A maximum average rectified forward current rating is sufficient for most
applications. The Schottky rectifier can be selected with lower forward current capability depending on the output
current Iout but has to be able to dissipate the power. The dissipated power, PD , is the average rectified forward
current times the diode forward voltage, Vforward .
(7)
Typically the diode should be able to dissipate around 500mW depending on the load current and forward
voltage.
Table 2. Rectifier Diode Selection
CURRENT
Vr
Vforward/Iavg
SUPPLIER
COMPONENT CODE
RATING Iavg
2 A
20 V
0.44 V / 2 A
Vishay Semiconductor
SL22
2 A
20 V
0.5 V / 2 A
Fairchild Semiconductor
SS22
Setting the Output Voltage
The output voltage is set by an external resistor divider. Typically, a minimum current of 50 mA flowing through
the feedback divider gives good accuracy and noise covering. A standard low side resistor of 18 k
is typically
selected. The resistors are then calculated as:
(8)
Compensation (COMP)
The regulator loop can be compensated by adjusting the external components connected to the COMP pin. The
COMP pin is the output of the internal transconductance error amplifier.
Standard values of RCOMP = 16 k and CCOMP = 2.7 nF will work for the majority of the applications.
See Table 3 for dedicated compensation networks giving an improved load transient response. The following
equations can be used to calculate RCOMP and CCOMP :
(9)
with
VIN
Minimum input voltage
VS
Output voltage
Cout
Output capacitance
L
Inductor value, e.g. 3.3 mH or 6.8 mH
Iout
Maximum output current in the application
Make sure that RCOMP < 120 k and CCOMP> 820 pF, independent of the results of the above formulas.
Copyright 2008–2010, Texas Instruments Incorporated
11
Product Folder Link(s): TPS61087
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