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| 型號： | TL2575HV-05IKV |
| 廠商： | TEXAS INSTRUMENTS INC |
| 元件分類： | 穩(wěn)壓器 |
| 英文描述： | 4 A SWITCHING REGULATOR, 63 kHz SWITCHING FREQ-MAX, PZFM5 |
| 封裝： | ROHS COMPLIANT, PLASTIC, TO-220, 5 PIN |
| 文件頁數(shù)： | 10/29頁 |
| 文件大小： | 1019K |
| 代理商： | TL2575HV-05IKV |
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V
= V
OUT
REF
1 +
where V
= 1.23 V
REF
(
R2
R1
(
R2 = R1
– 1
V
OUT
V
REF
C
7758
OUT
(F)
V
IN(Max)
V
L1(H)
OUT
1-A SIMPLE STEP-DOWN SWITCHING VOLTAGE REGULATORS
SLVS638B – MAY 2006 – REVISED JANUARY 2007
PROCEDURE (Adjustable Output)
EXAMPLE (Adjustable Output)
Known:
VOUT(Nom)
VOUT = 10 V
VIN(Max) = Maximum input voltage
VIN(Max) = 25 V
ILOAD(Max) = Maximum load current
ILOAD(Max) = 1 A
1. Programming Output Voltage (Selecting R1 and R2)
Referring to Fig. 2, VOUT is defined by:
Select R1 = 1 k
R2 = 1 (10/1.23 – 1) = 7.13 k
Select R2 = 7.15 k
(closest 1% value)
Choose a value for R1 between 1 k
and 5 k (use 1% metal-film
resistors for best temperature coefficient and stability over time).
2. Inductor Selection (L1)
A. Calculate the "set" volts-second (E
T) across L1:
A. Calculate the "set" volts-second (E
T) across L1:
E
T = (V
IN – VOUT) × ton
E
T = (25 – 10) × (10/25) × (1000/52) [Vs]
E
T = (V
IN – VOUT) × (VOUT/VIN) × {1000/fosc(in kHz)} [Vs]
E
T = 115 Vs
NOTE: Along with ILOAD, the "set" volts-second (ET) constant
establishes the minimum energy storage requirement for the
inductor.
B. Using Figure 19, select the appropriate inductor code based on
B. Using Figure 19, the intersection of 115 V
s and 1 A
the intersection of E
T value and I
LOAD(Max).
corresponds to an inductor code of H470.
C. From Table 2, choose the appropriate inductor based on the
C. H470
→ L1 = 470 F
inductor code. Parts from three well-known inductor manufacturers
Choose from:
are given. The inductor chosen should be rated for operation at
34048 (Schott)
52-kHz and have a current rating of at least 1.15 x ILOAD(Max) to
PE-53118 (Pulse Engineering)
allow for the ripple current. The actual peak current in L1 (in normal
operation) can be calculated as follows:
RL1961 (Renco)
IL1(pk) = ILOAD(Max) + (VIN – VOUT) × ton/2L1
Where ton = VOUT/VIN × (1/fosc)
3. Output Capacitor Selection (COUT)
A. The TL2575 control loop has a two-pole two-zero frequency
A.COUT ≥ 7785 × 25/(10 × 470) [F]
response. The dominant pole-zero pair is established by COUT and
COUT ≥ 41.4 F
L1. To meet stability requirements, COUT must meet the following
To obtain an acceptable output voltage ripple
→
requirement:
COUT = 220 F electrolytic
However, COUT may need to be several times larger than the
calculated value above in order to achieve an acceptable output
ripple voltage of ~0.01
× V
OUT.
B. COUT should have a voltage rating of at least 1.5 × VOUT. But if a
low output ripple voltage is desired, choose capacitors with a higher
voltage ratings than the minimum required due to their typically
lower ESRs.
4. Catch Diode Selection (D1) (see Table 1)
A. In normal operation, the catch diode requires a current rating of
A. Pick a diode with a 3-A rating.
at least 1.2
× I
LOAD(Max). For the most robust design, D1 should be
rated for a current equal to the TL2575 maximum switch peak
current; this represents the worst-case scenario of a continuous
short at VOUT.
B. The diode requires a reverse voltage rating of at least
B. Pick a 40-V rated Schottky diode (1N5822, MBR340, 31QD04, or
1.25
× V
IN(Max).
SR304) or 100-V rated Fast Recovery diode (31DF1, MURD310, or
HER302)
5. Input Capacitor (CIN)
An aluminum electrolytic or tantalum capacitor is needed for input
CIN = 100 F, 35 V, aluminum electrolytic
bypassing. Locate CIN as close to VIN and GND pins as possible.
18
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