參數(shù)資料
型號(hào): PQ05RG1
廠商: Sharp Corporation
英文描述: Low Power-Loss Voltage RegulatorsBuilt-in Reverse Voltage Protection Function Between Input and Output
中文描述: 低功率損耗電壓RegulatorsBuilt在反向輸入與輸出電壓保護(hù)功能
文件頁數(shù): 2/6頁
文件大?。?/td> 46K
代理商: PQ05RG1
Low Power-Loss Voltage Regulators
PQ05RG1/PQ05RG11 Series
Fig.1 Test Circuit
Fig.2 Test Circuit of Ripple Rejection
Parameter
Symbol
Conditions
V
O
R
eg
L
R
eg
I
T
C
V
O
RR
V
i
-
O
V
C
(
ON
)
I
C
(
ON
)
V
C
(
OFF
)
I
C
(
OFF
)
I
q
Output voltage
Load regulation
Line regulation
Temperature coefficient of output voltage
Ripple rejection
Dropout voltage
ON-state voltage for control
ON-state current for current
OFF-state voltage for control
OFF-state current for control
Quiescent current
*4
PQ05RG1/11
:V
IN
= 7V, I
O
=5mA to 1.0A
PQ09RG1/11
:V
IN
=11V, I
O
=5mA to 1.0A
PQ12RG1/11
:V
IN
=14V, I
O
=5mA to 1.0A
*5
PQ05RG1/11
:V
IN
= 6 to 16V
PQ09RG1/11
:V
IN
=10 to 20V
PQ12RG1/11
:V
IN
=13 to 23V
*6
PQ05RG1/11
:V
IN
= 7V
PQ09RG1/11
:V
IN
=11V
PQ12RG1/11
:V
IN
=14V
*7
Input voltage shall be the value when output voltage is 95% in comparison with the initial value.
*8
In case of opening control terminal
4
, output voltage turns on.
Unit
MAX.
5.25
9.45
12.6
5.12
9.22
12.3
2.0
2.5
-
-
0.5
-
20
0.8
-0.4
10.0
TYP.
5.0
9.0
12.0
5.0
9.0
12.0
0.3
0.1
±0.01
60
0.2
-
-
-
-
6.0
MIN.
4.75
8.55
11.4
4.88
8.78
11.7
-
-
-
45
-
2.0
-
-
-
-
PQ05RG1
PQ09RG1
PQ12RG1
PQ05RG11
PQ09RG11
PQ12RG11
V
O
=0.5A
IN
= 7V
V
IN
=11V
V
IN
=14V
*4
I
O
=5mA,
*5
I
O
=5mA, T
j
=0 to 125C,
*6
Refer to Fig. 2
*7
, I
O
=0.5A
*6
, I
O
=0.5A
*6
, I
O
=0.5A, V
C
=2.7V
*6
*6
, V
O
=0.4A
I
O
=0A,
*6
V
%
%
%/C
dB
V
V
μ
A
V
mA
mA
I
Electrical Characteristics
(Unless otherwise specified, condition shall be I
O
=0.5A,T
a
=25C
*4
)
V
IN
= 7V
V
IN
=11V
V
IN
=14V
*8
G
3
G
2
G
1
G
4
V
~
e
i
V
IN
V
C
I
O
e
o
R
L
0.33
μ
F
47
μ
F
+
+
~
G
3
G
2
G
1
G
4
A
V
A
A
V
IN
I
q
I
C
I
O
V
O
V
C
R
L
0.33
μ
F
47
μ
F
+
f=120Hz (sine wave)
e
i
=0.5V
rms
V
IN
= 7V (
PQ05RG1
/
PQ05RG11
)
V
IN
=11V (
PQ09RG1
/
PQ09RG11
)
V
IN
=14V (
PQ12RG1
/
PQ12RG11
)
I
O
=0.5A
RR=20 log (e
i
/e
o
)
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