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參數(shù)資料
| 型號： | OPA660AP |
| 元件分類： | 跨導放大器 |
| 英文描述： | Wide Bandwidth OPERATIONAL TRANSCONDUCTANCE AMPLIFIER AND BUFFER |
| 中文描述： | 寬帶運算跨導放大器和緩沖 |
| 文件頁數(shù)： | 10/18頁 |
| 文件大?。?/td> | 358K |
| 代理商： | OPA660AP |
10
OPA660
R
B
R
L
R
B
R
E
V–
V+
V
I
V
O
(a) Common-Emitter Amplifier
V
O
100
OTA
V
I
B
E
2
R
L
R
E
Non-Inverting Gain
V
OS
≈
0
(b) Common-E Amplifier
Inverting Gain
V several volts
3
C
8
Transconductance varies over temperature.
Transconductance remains constant over temperature.
V–
V+
V
I
V
O
(a) Common-Collector Amplifier
(Emitter Follower)
V
O
100
OTA
V
I
(b) Common-C Amplifier
(Buffer)
G 1
V 0.7V
G 1
V 0
B
3
C
8
R
E
R
E
R
O
=
1
g
m
G = 1
≈ 1
1 +
g
m
￥
R
E
E
2
using this more complex biasing circuitry. It does, however,
demonstrate the possibility of signal-controlled quiescent
current. This may suggest other possibilities such as AGC,
dynamic control of AC behavior, or VCO.
Figure 4 shows logic control of pin 1 used to disable the
OPA660. Zero/5V logic levels are converted to a 1mA/0mA
current connected to pin 1. The 1mA current flowing in R
Q
increases the voltage at pin 1 to approximately 1V above the
–5V rail. This will reduce I
Q
to near zero, disabling the
OPA660.
BASIC APPLICATIONS CIRCUITS
Most applications circuits for the OTA section consist of a
few basic types which are best understood by analogy to a
transistor. Just as the transistor has three basic operating
modes—common emitter, common base, and common col-
lector—the OTA has three equivalent operating modes com-
mon-E, common-B, and common-C. See Figures 5, 6, and 7.
50k
100
1
4
–5V
I
C
250
R
Q
Internal
Current Source
Circuitry
OPA660
2N2907
+5V
I = 0: OPA660 On
I 1mA: OPA660 Off
0/5V
Logic In
5V: OPA660 On
4.7k
FIGURE 7. Common-Base vs Common-B Amplifier.
FIGURE 6. Common-Collector vs Common-C Amplifier.
FIGURE 5. Common-Emitter vs Common-E Amplifier.
FIGURE 4. Logic-Controlled Disable Circuit.
Inverting Gain
V
OS
≈
0
V
I
V
O
(a) Common-Base
Amplifier
OTA
V
I
(b) Common-B Amplifier
R
L
Non-Inverting Gain
V several volts
R
E
V
O
R
L
R
E
B
E
2
3
C
8
G = – R
≈
–
R
E
+ g
m
L
1
R
L
R
E
V+
100
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