參數(shù)資料
型號: LT1996ACMS
廠商: LINEAR TECHNOLOGY CORP
元件分類: 運動控制電子
英文描述: Precision, 100uA Gain Selectable Amplifier
中文描述: OP-AMP, 160 uV OFFSET-MAX, 0.56 MHz BAND WIDTH, PDSO10
封裝: PLASTIC, MSOP-10
文件頁數(shù): 10/24頁
文件大小: 352K
代理商: LT1996ACMS
LT1996
10
1996f
Consider Figure 1. This shows the LT1996 configured as
a gain of 117 difference amplifier on a single supply with
Figure 3. Calculating Additional Voltage Range of
Inverting Inputs
These two voltages represent the high and low extremes
of the common mode input range, if the other limits have
not already been exceeded (1 and 3, above). In most cases,
the inverting inputs M9 through M81 can be taken further
than these two extremes because doing this does not
move the op amp input common mode. To calculate the
limit on this additional range, see Figure 3. Note that, with
Figure 1. Difference Amplifier Cannot Produce 0V on a Single
Supply. Provide a Negative Supply, or Raise Pin 5, or Provide
400
μ
V of V
DM
the output REF connected to ground. This is a great circuit,
but it does not support V
DM
= 0V at any common mode
because the output clips into ground while trying to
produce 0V
OUT
. It can be fixed simply by declaring the
valid input differential range not to extend below +0.4mV,
or by elevating the REF pin above 40mV, or by providing
a negative supply.
Calculating Input Voltage Range
Figure 2 shows the LT1996 in the generalized case of a
difference amplifier, with the inputs shorted for the com-
mon mode calculation. The values of R
F
and R
G
are
dictated by how the P inputs and REF pin are connected.
By superposition we can write:
V
INT
= V
EXT
(R
F
/(R
F
+ R
G
)) + V
REF
(R
G
/(R
F
+ R
G
))
Or, solving for V
EXT
:
V
EXT
= V
INT
(1 + R
G
/R
F
) – V
REF
R
G
/R
F
But valid V
INT
voltages are limited to V
CC
– 1.2V and V
EE
+
1V, so:
MAX V
EXT
= (V
CC
– 1.2) (1 + R
G
/R
F
) – V
REF
R
G
/R
F
and:
MIN V
EXT
= (V
EE
+ 1) (1 + R
G
/R
F
) – V
REF
R
G
/R
F
Figure 2. Calculating CM Input Voltage Range
V
MORE
= 0, the op amp output is at V
REF
. From the max
V
EXT
(the high cm limit), as V
MORE
goes positive, the op
amp output will go more negative from V
REF
by the amount
V
MORE
R
F
/R
G
, so:
V
OUT
= V
REF
– V
MORE
R
F
/R
G
Or:
V
MORE
= (V
REF
– V
OUT
) R
G
/R
F
The most negative that V
OUT
can go is V
EE
+ 0.04V, so:
Max V
MORE
= (V
REF
– V
EE
– 0.04V) R
G
/R
F
(should be positive)
The situation where this function is negative, and therefore
problematic, when V
REF
= 0 and V
EE
= 0, has already been
dealt with in Figure 1. The strength of the equation is
demonstrated in that it provides the three solutions
APPLICATIU
W
U
U
4pF
4pF
+
1996 F01
450k/81
450k/27
450k/9
450k/81
450k/27
450k/9
450k
450k
REF
5V
V
2.5V
V
DM
0V
+
8
7
6
5
4
9
10
1
2
3
LT1996
V
OUT
= 117 V
DM
+
V
REF
R
F
R
F
R
G
R
G
1996 F02
V
EXT
V
INT
V
CC
V
EE
+
V
REF
R
F
R
F
R
G
R
G
1996 F03
V
MAX OR MIN
V
INT
V
MORE
V
CC
V
EE
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