參數(shù)資料
型號(hào): LT1028CS8#TRPBF
廠商: Linear Technology
文件頁(yè)數(shù): 3/28頁(yè)
文件大?。?/td> 0K
描述: IC OP-AMP LOW NOISE SNGL 8-SOIC
標(biāo)準(zhǔn)包裝: 2,500
放大器類型: 通用
電路數(shù): 1
轉(zhuǎn)換速率: 15 V/µs
增益帶寬積: 75MHz
電流 - 輸入偏壓: 30nA
電壓 - 輸入偏移: 20µV
電流 - 電源: 7.6mA
電壓 - 電源,單路/雙路(±): ±4 V ~ 18 V
工作溫度: -40°C ~ 85°C
安裝類型: 表面貼裝
封裝/外殼: 8-SOIC(0.154",3.90mm 寬)
供應(yīng)商設(shè)備封裝: 8-SO
包裝: 帶卷 (TR)
LT1028/LT1128
11
1028fb
applicaTions inForMaTion – noise
Voltage Noise vs Current Noise
The LT1028/LT1128’s less than 1nV/√Hz voltage noise is
three times better than the lowest voltage noise heretofore
available (on the LT1007/1037). A necessary condition for
such low voltage noise is operating the input transistors at
nearly 1mA of collector currents, because voltage noise is
inversely proportional to the square root of the collector
current. Current noise, however, is directly proportional
to the square root of the collector current. Consequently,
the LT1028/LT1128’s current noise is significantly higher
than on most monolithic op amps.
Therefore, to realize truly low noise performance it is
important to understand the interaction between voltage
noise (en), current noise (In) and resistor noise (rn).
Total Noise vs Source Resistance
The total input referred noise of an op amp is given by:
et = [en2 + rn2 + (InReq)2]1/2
where Req is the total equivalent source resistance at the
two inputs, and
rn = √4kTReq = 0.13√Req in nV/√Hz at 25°C
As a numerical example, consider the total noise at 1kHz
of the gain 1000 amplifier shown in Figure 1.
the largest term, as in the example above, and the LT1028/
LT1128’s voltage noise becomes negligible. As Req is
further increased, current noise becomes important. At
1kHz, when Req is in excess of 20k, the current noise
component is larger than the resistor noise. The total
noise versus matched source resistance plot illustrates
the above calculations.
The plot also shows that current noise is more dominant
at low frequencies, such as 10Hz. This is because resistor
noise is flat with frequency, while the 1/f corner of current
noise is typically at 250Hz. At 10Hz when Req > 1k, the
current noise term will exceed the resistor noise.
When the source resistance is unmatched, the total noise
versus unmatched source resistance plot should be con-
sulted. Note that total noise is lower at source resistances
below 1k because the resistor noise contribution is less.
When RS > 1k total noise is not improved, however. This
is because bias current cancellation is used to reduce
input bias current. The cancellation circuitry injects two
correlated current noise components into the two inputs.
With matched source resistors the injected current noise
creates a common-mode voltage noise and gets rejected
by the amplifier. With source resistance in one input only,
the cancellation noise is added to the amplifier’s inherent
noise.
In summary, the LT1028/LT1128 are the optimum am-
plifiers for noise performance, provided that the source
resistanceiskeptlow.Thefollowingtabledepictswhichop
amp manufactured by Linear Technology should be used
to minimize noise, as the source resistance is increased
beyond the LT1028/LT1128’s level of usefulness.
Table 1. Best Op Amp for Lowest Total Noise vs Source Resistance
SOURCE RESIS-
TANCE (Ω) (Note 1)
BEST OP AMP
AT LOW FREQ (10Hz)
WIDEBAND (1kHz)
0 to 400
LT1028/LT1128
400 to 4k
LT1007/1037
LT1028/LT1128
4k to 40k
LT1001
LT1007/LT1037
40k to 500k
LT1012
LT1001
500k to 5M
LT1012 or LT1055
LT1012
>5M
LT1055
Note 1: Source resistance is defined as matched or unmatched, e.g.,
RS = 1k means: 1k at each input, or 1k at one input and zero at the other.
Req = 100Ω + 100Ω || 100k ≈ 200Ω
rn = 0.13√200 = 1.84nV√Hz
en = 0.85nV√Hz
In = 1.0pA/√Hz
et = [0.852 + 1.842 + (1.0 × 0.2)2]1/2 = 2.04nV/√Hz
Output noise = 1000 et = 2.04V/√Hz
At very low source resistance (Req < 40Ω) voltage noise
dominates. As Req is increased resistor noise becomes
+
100
100k
100
LT1028
LT1128
1028 F01
Figure 1
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