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參數(shù)資料
| 型號(hào)： | IRU431LCS |
| 英文描述： | VOLT REGULATOR|ADJUSTABLE|+1.24 TO +15V|BIPOLAR|SOP|8PIN|PLASTIC |
| 中文描述： | 電壓調(diào)節(jié)器|調(diào)節(jié)| 1.24至15V |雙極|?？苵 8引腳|塑料 |
| 文件頁數(shù)： | 4/6頁 |
| 文件大?。?/td> | 93K |
| 代理商： | IRU431LCS |
IRU431L / IRU431AL
4
Rev. 1.5
07/13/01
APPLICATION INFORMATION
The maximum value for the biasing resistor is calcu-
lated using the following equations:
Where:
V
MIN
= Minimum supply voltage
I
L(MAX)
= Maximum load current
I
B(MAX)
= Maximum bias current
I
K(MIN)
= Maximum value for the minimum
cathode current spec
I
R
= Current through R1
Assuming R1 = 2K
as before,
The maximum power dissipation of the resistor is
calculated under the maximum supply voltage as
follows:
Thermal Design
The IRU431L is offered in the plastic 8-pin SOIC or the
surface mount SOT-23 (L) packages. The 8-pin SOIC
package has the maximum power dissipation capability
of 775mW at Ta=25
°
C with the derating factor of -6.2mW/
°
C. The SOT-23 package has the maximum power dis-
sipation capability of 150mW at Ta =25
°
C with the der-
ating factor of -1.2mW /
°
C.
Output Voltage Setting
The IRU431L can be programmed to any voltages in the
range of 1.24 to 15V with the addition of R1 and R2
external resistors according to the following formula:
The IRU431L keeps a constant voltage of 1.240V be-
tween the Ref pin and ground pin. By placing a resistor
R2 across these two pins a constant current flows
through R2, adding to the Iref current and into the R1
resistor producing a voltage equal to:
which will be added to the 1.240V to set the output volt-
age as shown in the above equation. Since the input
bias current of the Ref pin is 0.5
μ
A max, it adds a very
small error to the output voltage and for most applica-
tions can be ignored. For example, in a typical 5V to
3.3V application where R2=1.21K
and R1=2K
the
error due to the Iadj is only 1mV which is about 0.03% of
the nominal set point.
Figure 3 - Typical application of the
IRU431L for programming the output voltage.
Biasing Resistor (R
B
) Selection
The biasing resistor R
B
is selected such that it does not
limit the input current under the minimum input supply
and maximum load and biasing current.
An example is given below on how to properly select the
biasing resistor.
Assuming:
V
MIN
= 4.5V
V
MAX
= 6V
V
KA
= 3.3V
I
L
= 10mA
431app2-1.0
V
R2
Co
R1
R
IRU431L
I
R
K
I
L
V
KA
= V
O
B
IN
L
P
R
B
(MAX)
=
Where:
V
MAX
= Maximum supply voltage
P
R
B
(MAX)
= Maximum RB power dissipation
P
R
B
(MAX)
= (6 - 3.3)
100
2
(V
MAX
- V
KA
)
R
B
2
R
B(MAX)
=
I
B(MAX)
= I
K(MIN)
+ I
R
V
MIN
- V
KA
I
B(MAX)
+ I
L(MAX)
I
R
= 3.3 - 1.24
2
I
B(MAX)
= 0.08 + 1.03 = 1.11mA
R
B(MAX)
= 4.5 - 3.3
1.11 +10
Selecting R
B
= 100
Vo = V
KA
= Vref
×
o
1 +
p
+ Iref
×
R1
R1
R2
(1.240 / R2)
×
R1 + Iref
×
R1
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