參數(shù)資料
型號(hào): IRU3011
廠商: International Rectifier
英文描述: 5-BIT PROGRAMMABLE SYNCHRONOUS BUCK CONTROLLER IC
中文描述: 5位可編程同步降壓控制器IC
文件頁數(shù): 9/13頁
文件大?。?/td> 77K
代理商: IRU3011
IRU3011
9
Rev. 1.6
08/20/02
www.irf.com
T
Switching Period
D
Duty Cycle
Vsw
High-side MOSFET ON Voltage
R
DS
MOSFET On-Resistance
Vsync
Synchronous MOSFET ON Voltage
Ir
Inductor Ripple Current
Vo
Output Ripple Voltage
T = 1/Fsw
Vsw = Vsync = Io
×
R
DS
D
(Vo + Vsync) / (V
IN
- Vsw + Vsync)
T
ON
= D
×
T
T
OFF
= T - T
ON
Ir = (Vo + Vsync)
×
T
OFF
/ L
Vo =
Ir
×
ESR
L = 0.006
×
9000
×
(4.75 - 2.8) / (2
×
14.2) = 3.7
μ
H
L = ESR
×
C
×
(V
IN(MIN)
- Vo
(MAX)
) / (2
×
I)
T = 1 / 200000 = 5
μ
s
Vsw = Vsync = 14.2
×
0.019 = 0.27V
D
(2.8 + 0.27) / (5 - 0.27 + 0.27) = 0.61
T
ON
= 0.61
×
5 = 3.1
μ
s
T
OFF
= 5 - 3.1 = 1.9
μ
s
Ir = (2.8 + 0.27)
×
1.9 / 3 = 1.94A
Vo = 1.94
×
0.006 = 0.011V = 11mV
Ts = T
J
- P
D
×
(
θ
JC
+
θ
cs)
Ts = 125 - 3.82
×
(1.8 + 0.05) = 118
8
C
T = Ts - T
A
= 118 - 35 = 83
8
C
Temperature Rise Above Ambient
θ
SA
=
T / P
D
= 83 / 3.82 = 22
8
C/W
Output Inductor Selection
The output inductance must be selected such that un-
der low line and the maximum output voltage condition,
the inductor current slope times the output capacitor
ESR is ramping up faster than the capacitor voltage is
drooping during a load current step. However, if the in-
ductor is too small, the output ripple current and ripple
voltage become too large. One solution to bring the ripple
current down is to increase the switching frequency,
however, that will be at the cost of reduced efficiency
and higher system cost. The following set of formulas
are derived to achieve the optimum performance without
many design iterations.
The maximum output inductance is calculated using the
following equation:
Where:
V
IN(MIN)
= Minimum input voltage
For Vo=2.8V and
I=14.2A
Assuming that the programmed switching frequency is
set at 200KHz, an inductor is designed using the
Micrometals’ powder iron core material. The summary
of the design is outlined below:
The selected core material is Powder Iron, the selected
core is T50-52D from Micro Metal wounded with 8 turns
of #16 AWG wire, resulting in 3
μ
H inductance with
3m
of DC resistance.
Assuming L=3
μ
H and Fsw=200KHz(switching fre-
quency), the inductor ripple current and the output ripple
voltage is calculated using the following set of equations:
In our example for Vo=2.8V and 14.2A load, assuming
IRL3103 MOSFET for both switches with maximum on
resistance 0f 19m
, we have:
Power Component Selection
Assuming IRL3103 MOSFETs as power components,
we will calculate the maximum power dissipation as fol-
lows:
For high-side switch the maximum power dissipation
happens at maximum Vo and maximum duty cycle.
D
MAX
(2.8 + 0.27) / (4.75 - 0.27 + 0.27) = 0.65
P
DH
= D
MAX
×
Io
2
×
R
DS(MAX)
P
DH
= 0.65
×
14.2
2
×
0.029 = 3.8W
R
DS(MAX)
= Maximum R
DS(ON)
of the MOSFET at 125
8
C
For synch MOSFET, maximum power dissipation hap-
pens at minimum Vo and minimum duty cycle.
D
MIN
(2 + 0.27) / (5.25 - 0.27 + 0.27) = 0.43
P
DS
= (1 - D
MIN
)
×
Io
2
×
R
DS(MAX)
P
DS
= (1 - 0.43)
×
14.2
2
×
0.029 = 3.33W
Heat Sink Selection
Selection of the heat sink is based on the maximum
allowable junction temperature of the MOSFETS. Since
we previously selected the maximum R
DS(ON)
at 125
8
C,
then we must keep the junction below this temperature.
Selecting TO-220 package gives
θ
JC
=1.8
8
C/W (From the
venders’ data sheet) and assuming that the selected
heat sink is black anodized, the heat-sink-to-case ther-
mal resistance is
θ
cs=0.05
8
C/W, the maximum heat sink
temperature is then calculated as:
With the maximum heat sink temperature calculated in
the previous step, the heat-sink-to-air thermal resistance
(
θ
SA
) is calculated as follows:
Assuming T
A
= 35
8
C:
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