參數(shù)資料
型號: IRU1030-33CT
廠商: International Rectifier
英文描述: VOLT REGULATOR|FIXED|+3.3V|BIPOLAR|SIP|3PIN|PLASTIC
中文描述: 電壓調節(jié)器|定額| 3.3 |雙極|園區(qū)| 3針|塑料
文件頁數(shù): 6/11頁
文件大?。?/td> 70K
代理商: IRU1030-33CT
6
Rev. 1.3
08/20/02
IRU1030
www.irf.com
Figure 5 - Typical regulator response to
the fast load current step.
An example of a regulator design to meet the Intel
Pentium Pro GTL+ specification is given below.
Assume the specification for the processor as shown in
Table 1:
Table 1 - GTL+ Specification for Pentium Pro
The first step is to select the voltage step allowed in the
output due to the output capacitor’s ESR:
1) Assuming the regulator’s initial accuracy plus the re-
sistor divider tolerance is
±
30mV (
±
2% of 1.5V nomi-
nal), then the total step allowed for the ESR and the
ESL, is
120 mV.
Assuming that the ESL drop is
10mV, the remain-
ing ESR step will be
110mV. Therefore the output
capacitor ESR must be:
The Sanyo MVGX series is a good choice to achieve
both price and performance goals. The 6MV1500GX,
1500
μ
F, 6.3V has an ESR of less than 36m
typ.
Selecting a single capacitor achieves our design goal.
The next step is to calculate the drop due to the ca-
pacitance discharge and make sure that this drop in
voltage is less than the selected ESL drop in the
previous step.
V
ESR
V
ESL
V
C
T
LOAD
CURRENT
LOAD CURRENT RISE TIME
1030plt1-1.0
C
IN
= 2.7
μ
F
0.15
×
50
ESR = (3.3 - 1.5 - 1.2 - 0.15)
2.7
ESR =(V
IN
- V
OUT
-
V - V
DROP
)
I
Vc = t
C
×
I
2
×
2.7
1500
2) With the output capacitance being 1500
μ
F:
Where:
t = 2
μ
s is the regulator response time
To set the output DC voltage, we need to select R1 and
R2:
3) Assuming R1 = 121
, 0.5%:
Select R2 = 24.3
, 0.5%
Selecting both R1 and R2 resistors to be 0.5% toler-
ance, results in the least amount of error introduced
by the resistor dividers leaving
±
1.3% error budget
for the IRU1030 reference which is within the initial
accuracy of the device.
Finally, the input capacitor is selected as follows:
4) Assuming that the input voltage can drop 150mV be-
fore the main power supply responds, and that the
main power supply response time is
50
μ
s, then
the minimum input capacitance for a 2.7A load step
is given by:
The ESR should be less than:
Where:
V
DROP
L
Input voltage drop allowed in step 4
V
L
Maximum regulator dropout voltage
I
L
Load current step
Selecting a single 1500
μ
F the same type as the output
capacitors exceeds our requirements. However, the same
input capacitor can also support the second regulator
for the other end of termination.
R2 = V
R1 = 1.25-1
×
121 = 24.2
REF
-1
V
OUT
1.5
Type of V
OUT
I
MAX
Max Allowed
Processor Nominal Output Tolerance
Pentium Pro 1.50 V 2.7 A
±
150 mV
ESR
110
2.7
相關PDF資料
PDF描述
IRU1050 5A LOW DROPOUT POSITIVE ADJUSTABLE REGULATOR
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