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參數(shù)資料
| 型號： | EV0034 |
| 廠商： | Monolithic Power Systems, Inc. |
| 英文描述： | 2A, 1.3MHz Step-Up Converter |
| 中文描述： | 第2A，1.3MHz升壓轉(zhuǎn)換器 |
| 文件頁數(shù)： | 12/14頁 |
| 文件大?。?/td> | 279K |
| 代理商： | EV0034 |
MP1527
2A, 1.3MHz
Step-Up Converter
MP1527 Rev 1.8_8/31/05
Monolithic Power Systems, Inc.
12
Monolithic Power Systems
C3
≈
1.9x10
3
C2 V
OUT
2
/ (V
IN
R3
2
)
In some cases, if an output capacitor with high
capacitance
and
high
resistance (ESR) is used, then a second
compensation capacitor (from COMP to
SGND) is required to compensate for the zero
introduced by the output capacitor ESR. The
extra capacitor is required if the ESR zero is
less than 4x the crossover frequency. The
ESR zero frequency is:
f
ZESR
= 1 / (2
π
*C2*R
ESR
)
The
second
compensation
required if:
4*f
C
≥
f
ZESR
or
4*G
CS
*G
EA
*V
IN
*V
FB
*R3
/
(2
π
*C2*R
ESR
)
Simplifying:
(8.4x10
-3
*V
IN
*R3*R
ESR
)/ V
OUT
If this is the case, calculate the second
compensation capacitor by the equation:
R3*C4 = C2*R
ESR
or
C4 = (C2*R
ESR
) / R3
equivalent
series
capacitor
is
(2
π
*C2*V
OUT
2
)
≥
1
/
2
≥
1
Example
Given:
Input Voltage (V
IN
): 5V
Output Voltage (V
OUT
): 12V
Maximum Load Current (I
LOAD-MAX
): 500mA
Output Capacitor (C2): 10
μ
F (ESR=10m
Maximum)
Inductor Value (L): 4.7
μ
H
Find the frequency of the right-half-plane zero:
f
RHPZ
= V
IN
f
RHPZ
= (5V)
2
/
(2
π
*4.7
μ
H*12V*500mA)=141KHz
The frequency of the right-half-plane zero is
less than 750khz, so use equation (1) to
determine the compensation resistor R3:
R3
≈
48*V
IN
*V
OUT
*C2 / (L*I
LOAD-MAX
)
R3
≈
48*5*12*10
μ
F/(4.7
μ
H*500mA) =12.3K
(use 10K
)
Find the compensation capacitor C3:
C3
≈
1.9x10
3
*C2*V
OUT
C3
≈
1.9x10
3
*10
μ
F (12V)
2
/ (5 * 10K
2
) = 5.4nF
(use the nearest standard value, 5.6nF)
Determine
if
the
second
capacitor is required:
8.4x10
-3
* 5V * 5.6K
* 10m
/ 12V
2
= 0.016
≤
1
Therefore no second compensation capacitor
is required.
2
/ (2
π
*L*V
OUT
*I
LOAD-MAX
)
2
/ (V
IN
*R3
2
)
compensation
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