參數(shù)資料
型號: AD8034ARTZ-REEL
廠商: Analog Devices Inc
文件頁數(shù): 15/25頁
文件大?。?/td> 0K
描述: IC OPAMP VF R-R DUAL LN SOT23-8
標(biāo)準(zhǔn)包裝: 10,000
系列: FastFET™
放大器類型: 電壓反饋
電路數(shù): 2
輸出類型: 滿擺幅
轉(zhuǎn)換速率: 80 V/µs
-3db帶寬: 80MHz
電流 - 輸入偏壓: 1.5pA
電壓 - 輸入偏移: 1000µV
電流 - 電源: 3.3mA
電流 - 輸出 / 通道: 60mA
電壓 - 電源,單路/雙路(±): 5 V ~ 24 V,±2.5 V ~ 12 V
工作溫度: -40°C ~ 85°C
安裝類型: 表面貼裝
封裝/外殼: SOT-23-8
供應(yīng)商設(shè)備封裝: SOT-23-8
包裝: 帶卷 (TR)
AD8033/AD8034
Rev. D | Page 21 of 24
When selecting components, the common-mode input capacitance
must be taken into consideration.
Filter cutoff frequencies can be increased beyond 1 MHz using the
AD8033/AD8034 but limited open-loop gain and input impedance
begin to interfere with the higher Q stages. This can cause early
roll-off of the overall response.
Additionally, the stop-band attenuation decreases with decreasing
open-loop gain.
Keeping these limitations in mind, a 2-pole Sallen-Key Butterworth
filter with fC = 4 MHz can be constructed that has a relatively
low Q of 0.707 while still maintaining 15 dB of attenuation an
octave above fC and 35 dB of stop-band attenuation. The filter
and response are shown in Figure 60 and Figure 61, respectively.
–VS
+VS
VIN
R1
2.49k
C3
22pF
VOUT
AD8033
R2
2.49k
R5
49.9
C1
10pF
02
92
4-
06
0
Figure 60. 2-Pole Butterworth Active Filter
100M
100k
1M
FREQUENCY (Hz)
–45
GA
IN
(
d
B
)
–40
–35
–30
–25
–20
–15
–10
–5
0
5
0
29
24-
0
61
10M
Figure 61. 2-Pole Butterworth Active Filter Response
WIDEBAND PHOTODIODE PREAMP
Figure 62 shows an I/V converter with an electrical model of a
photodiode.
The basic transfer function is
F
PHOTO
OUT
R
sC
R
I
V
+
×
=
1
where IPHOTO is the output current of the photodiode, and the
parallel combination of RF and CF sets the signal bandwidth.
CS
RSH = 1011
VB
IPHOTO
02924-
062
RF
CF
VOUT
CM
RF
CM
CD
CF + CS
Figure 62. Wideband Photodiode Preamp
The stable bandwidth attainable with this preamp is a function
of RF, the gain bandwidth product of the amplifier, and the total
capacitance at the summing junction of the amplifier, including
CS and the amplifier input capacitance. RF and the total capacitance
produce a pole in the loop transmission of the amplifier that
can result in peaking and instability. Adding CF creates a zero
in the loop transmission that compensates for the effect of the
pole and reduces the signal bandwidth. It can be shown that the
signal bandwidth resulting in a 45°phase margin (f(45)) is defined
by the expression
S
F
CR
C
R
f
×
π
=
2
)
45
(
where:
fCR is the amplifier crossover frequency.
RF is the feedback resistor.
CS is the total capacitance at the amplifier summing junction
(amplifier + photodiode + board parasitics).
The value of CF that produces f(45) is
CR
F
S
F
f
R
C
×
π
=
2
The frequency response in this case shows about 2 dB of
peaking and 15% overshoot. Doubling CF and cutting the
bandwidth in half results in a flat frequency response, with
about 5% transient overshoot.
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