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參數(shù)資料
| 型號： | AD2S80AUE |
| 廠商： | ANALOG DEVICES INC |
| 元件分類： | 位置變換器 |
| 英文描述： | Variable Resolution, Monolithic Resolver-to-Digital Converter |
| 中文描述： | SYNCHRO OR RESOLVER TO DIGITAL CONVERTER, CQCC44 |
| 封裝： | CERAMIC, LCC-44 |
| 文件頁數(shù)： | 12/16頁 |
| 文件大?。?/td> | 268K |
| 代理商： | AD2S80AUE |
AD2S80A
REV. A
–12–
12
–12
f
BW
–6
–9
0.04f
BW
0.02f
BW
0
–3
3
6
9
0.4f
BW
0.2f
BW
FREQUENCY
0.1f
BW
G
2f
BW
Figure 4. AD2S80A Gain Plot
180
–180
P
f
BW
–90
–135
0.04f
BW
0.02f
BW
0
–45
45
90
135
0.4f
BW
0.2f
BW
FREQUENCY
0.1f
BW
2f
BW
Figure 5. AD2S80A Phase Plot
OUTPUT
POSITION
t
2
t
1
TIME
Figure 6. AD2S80A Small Step Response
T he small signal step response is shown in Figure 6. T he time
from the step to the first peak is t
1
and the t
2
is the time from
the step until the converter is settled to 1 LSB. T he times t
1
and
t
2
are given approximately by
t
1
=
1
f
BW
t
2
=
5
f
BW
×
R
12
where R = resolution, i.e., 10, 12, 14 or 16.
T he large signal step response (for steps greater than 5 degrees)
applies when the error voltage exceeds the linear range of the
converter.
T ypically the converter will take 3 times longer to reach the first
peak for a 179 degrees step.
In response to a velocity step, the velocity output will exhibit the
same time response characteristics as outlined above for the po-
sition output.
ACCE LE RAT ION E RROR
A tracking converter employing a T ype 2 servo loop does not
suffer any velocity lag, however, there is an additional error due
to acceleration. T his additional error can be defined using the
acceleration constant K
A
of the converter.
Input Acceleration
Error inOutput Angle
K
A
=
T he numerator and denominator must have consistent angular
units. For example if K
A
is in sec
-2
, then the input acceleration
may be specified in degrees/sec
2
and the error output in degrees.
Angular measurement may also be specified using radians, min-
utes of arc, LSBs, etc.
K
A
does not define maximum input acceleration,
only the error due
to it’s acceleration. T he maximum acceleration allowable before
the converter loses track is dependent on the angular accuracy
requirements of the system.
Angular Accuracy
×
K
A
=
Degrees
/
sec
2
K
A
can be used to predict the output position error for a
given input acceleration. For example for an acceleration of
100 revs/sec
2
, K
A
= 2.7
×
10
6
sec
-2
and 12-bit resolution.
Error inLSBs
=
Inputacceleration
[
LSB
/
sec
2
]
K
A
[sec
±2
]
=
100[
rev
/
sec
2
]
×
2
12
2.7
×
10
6
T o determine the value of K
A
based on the passive components
used to define the dynamics of the converter the following
should be used.
4.04
×
10
11
2
n
·
R
6·
R
4·(
C
4
+
C
5)
Where n = resolution of the converter.
R4, R6 in ohms
C5, C4 in farads
=
0.15
LSBsor
47.5
secondsof arc
K
A
=
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